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	<title>Comments for </title>
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		<title>Comment on please help physics question? by gp4rts</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/please-help-physics-question/comment-page-1/#comment-3664</link>
		<dc:creator>gp4rts</dc:creator>
		<pubDate>Fri, 10 Sep 2010 08:42:58 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/please-help-physics-question/#comment-3664</guid>
		<description>V = -dΦ/dt, where Φ is the total flux in webers.  1 tesla = 1 wb/m².  For constant field of 0.10 T,

V = -0.10*dA/dt

where A is the normal component of the coil area in the direction of the field

A =π*r²*cps(ω*t)

dA/dT = -ω*π*r²*sin(ω*t)

the peak value of  dA/dt is -ω*π*r²   (where sin = 1)

so

Vp = 0.10*ω*π*r² per turn of the coil

The number of turns is 5.1/(2*π*r), so total voltage is

Vt = 5.1/(2*π*r)*0.10*ω*π*r² = 0.255*ω*r

Vt = 2.14 v</description>
		<content:encoded><![CDATA[<p>V = -dΦ/dt, where Φ is the total flux in webers.  1 tesla = 1 wb/m².  For constant field of 0.10 T,</p>
<p>V = -0.10*dA/dt</p>
<p>where A is the normal component of the coil area in the direction of the field</p>
<p>A =π*r²*cps(ω*t)</p>
<p>dA/dT = -ω*π*r²*sin(ω*t)</p>
<p>the peak value of  dA/dt is -ω*π*r²   (where sin = 1)</p>
<p>so</p>
<p>Vp = 0.10*ω*π*r² per turn of the coil</p>
<p>The number of turns is 5.1/(2*π*r), so total voltage is</p>
<p>Vt = 5.1/(2*π*r)*0.10*ω*π*r² = 0.255*ω*r</p>
<p>Vt = 2.14 v</p>
]]></content:encoded>
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	<item>
		<title>Comment on Physics Homework Help Anyone? by TooKewl</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/physics-homework-help-anyone/comment-page-1/#comment-3621</link>
		<dc:creator>TooKewl</dc:creator>
		<pubDate>Thu, 09 Sep 2010 08:45:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/physics-homework-help-anyone/#comment-3621</guid>
		<description>Hey!

I can&#039;t answer all of the questions, but I think I know the answers to two of them.

The answer to question 2 is b.

and

The answer to question 8 is a.

I hope I helped. </description>
		<content:encoded><![CDATA[<p>Hey!</p>
<p>I can&#8217;t answer all of the questions, but I think I know the answers to two of them.</p>
<p>The answer to question 2 is b.</p>
<p>and</p>
<p>The answer to question 8 is a.</p>
<p>I hope I helped.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Physics Homework Help Anyone? by John R</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/physics-homework-help-anyone/comment-page-1/#comment-3620</link>
		<dc:creator>John R</dc:creator>
		<pubDate>Thu, 09 Sep 2010 08:45:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/physics-homework-help-anyone/#comment-3620</guid>
		<description>You may check physics homework help website below.</description>
		<content:encoded><![CDATA[<p>You may check physics homework help website below.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Generators And Motor Questions, know them? by goober</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-and-motor-questions-know-them/comment-page-1/#comment-3583</link>
		<dc:creator>goober</dc:creator>
		<pubDate>Wed, 08 Sep 2010 11:07:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-and-motor-questions-know-them/#comment-3583</guid>
		<description>1. C, the heaviest wire.
2. AC
3. DC
4. The closest one is watts, but that is power or work per unit time. Work is measured in Joules.
5. Watts
6. Currents generate magnetic fields that spin the motor.
7. magnetic fields generate electrical fields in moving conductors that make electrons move
8.direct current
9. alternating current
10. it converts mechanical energy into electrical energy</description>
		<content:encoded><![CDATA[<p>1. C, the heaviest wire.<br />
2. AC<br />
3. DC<br />
4. The closest one is watts, but that is power or work per unit time. Work is measured in Joules.<br />
5. Watts<br />
6. Currents generate magnetic fields that spin the motor.<br />
7. magnetic fields generate electrical fields in moving conductors that make electrons move<br />
8.direct current<br />
9. alternating current<br />
10. it converts mechanical energy into electrical energy</p>
]]></content:encoded>
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	<item>
		<title>Comment on homework help? (5 multiple choice) =]? by vkvanil</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/homework-help-5-multiple-choice/comment-page-1/#comment-3561</link>
		<dc:creator>vkvanil</dc:creator>
		<pubDate>Tue, 07 Sep 2010 13:31:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/homework-help-5-multiple-choice/#comment-3561</guid>
		<description>1 (D);  2(B); 3(C); 4(B); 5(D)</description>
		<content:encoded><![CDATA[<p>1 (D);  2(B); 3(C); 4(B); 5(D)</p>
]]></content:encoded>
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		<title>Comment on Generators use a magnetic field of which of the following to produce an electric current? by Nana</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/comment-page-1/#comment-3535</link>
		<dc:creator>Nana</dc:creator>
		<pubDate>Mon, 06 Sep 2010 11:07:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/#comment-3535</guid>
		<description>electromagnetic induction</description>
		<content:encoded><![CDATA[<p>electromagnetic induction</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Generators use a magnetic field of which of the following to produce an electric current? by Brian G</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/comment-page-1/#comment-3534</link>
		<dc:creator>Brian G</dc:creator>
		<pubDate>Mon, 06 Sep 2010 11:07:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/#comment-3534</guid>
		<description>I disagree.  I would go with &quot;all of the above.&quot;</description>
		<content:encoded><![CDATA[<p>I disagree.  I would go with &quot;all of the above.&quot;</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Generators use a magnetic field of which of the following to produce an electric current? by P A</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/comment-page-1/#comment-3533</link>
		<dc:creator>P A</dc:creator>
		<pubDate>Mon, 06 Sep 2010 11:07:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/generators-use-a-magnetic-field-of-which-of-the-following-to-produce-an-electric-current/#comment-3533</guid>
		<description>its definitely option C</description>
		<content:encoded><![CDATA[<p>its definitely option C</p>
]]></content:encoded>
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	<item>
		<title>Comment on I need help with 2 basic quetions? by science teacher</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/i-need-help-with-2-basic-quetions/comment-page-1/#comment-3506</link>
		<dc:creator>science teacher</dc:creator>
		<pubDate>Sun, 05 Sep 2010 11:07:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/i-need-help-with-2-basic-quetions/#comment-3506</guid>
		<description>A motor works by running current through a coil that creates an electromagnet that attracts an arm. A DC motor uses a make and break circuit to keep the arm rotating. An AC motor uses a commutator to change the direction of the attraction, as the direction of the power changes,  so that the arm keeps rotating. This rotational motion is used to cause something to rotate such as a saw blade, or through gears change the direction of the motion.

A generator uses outside motion such as steam, water power, moving water, wind, to move a coil past a magnet. This movement causes a current to run in the coil , this is electricity.</description>
		<content:encoded><![CDATA[<p>A motor works by running current through a coil that creates an electromagnet that attracts an arm. A DC motor uses a make and break circuit to keep the arm rotating. An AC motor uses a commutator to change the direction of the attraction, as the direction of the power changes,  so that the arm keeps rotating. This rotational motion is used to cause something to rotate such as a saw blade, or through gears change the direction of the motion.</p>
<p>A generator uses outside motion such as steam, water power, moving water, wind, to move a coil past a magnet. This movement causes a current to run in the coil , this is electricity.</p>
]]></content:encoded>
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	<item>
		<title>Comment on what is the max emf output? what would be the max emf output if 10 such loops were used instead? by Steve</title>
		<link>http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/what-is-the-max-emf-output-what-would-be-the-max-emf-output-if-10-such-loops-were-used-instead/comment-page-1/#comment-3445</link>
		<dc:creator>Steve</dc:creator>
		<pubDate>Sat, 04 Sep 2010 08:43:56 +0000</pubDate>
		<guid isPermaLink="false">http://www.magneticgeneratorguide.com/magnetic-generator-q-and-as/what-is-the-max-emf-output-what-would-be-the-max-emf-output-if-10-such-loops-were-used-instead/#comment-3445</guid>
		<description>The formula is
emf = NBAω = NBA(2πf) = 1*.015*(.1*.1)(2π*60) 
emf = .0565 V

Clearly, 10 loops would produce 10 times the emf......</description>
		<content:encoded><![CDATA[<p>The formula is<br />
emf = NBAω = NBA(2πf) = 1*.015*(.1*.1)(2π*60)<br />
emf = .0565 V</p>
<p>Clearly, 10 loops would produce 10 times the emf&#8230;&#8230;</p>
]]></content:encoded>
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