A generator uses a coil that has 150 turns and a 0.21-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf has an rms value of 120 V. Assuming that each turn of the coil is a square (an approximation), determine the length of the wire from which the coil is made.
What I’ve done:
E=NABw
E=(N)(L^2)(B)(2pi)(f)
(120)(square root 2) = (150)(L^2)(.21)(2pi)(60)
L=0.12m
This was counted as incorrect. Any ideas of where I could have gone wrong?
27. May 2010 at 8:43 pm
L^2 is coil area, so L is the length of a side of the square, right?
Then the length of wire used is 4L*150 m.
Depending on the precision they’re looking for, you may want to use a better value of L, 0.11945 m.